Difference between revisions of "Rope around the Earth"
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Taking ''l'' = 2π feet of slack and ''R'' = R <sub>earth</sub> = 20925524.9 feet from the initial problem the first approximation yields 614.766, demonstrating the accuracy and precision of these approximations. The second approximation yields 614.771, which is more precise than the first, but really only by a negligible amount, and simply highlights the accuracy of the first. On the scale of the Earth, there is a decent margin of error in measurements: the earth is not a perfect sphere, ropes stretch with strain, objects expand and contract with heat. The result is that these approximations are far more accurate and precise than our measurements can ever be.
Taking ''l'' = 2π feet of slack and ''R'' = R <sub>earth</sub> = 20925524.9 feet from the initial problem the first approximation yields 614.766, demonstrating the accuracy and precision of these approximations.The second approximation yields 614.771, which is more precise than the first, but really only by a negligible amount, and simply highlights the accuracy of the first. On the scale of the Earth, there is a decent margin of error in measurements: the earth is not a perfect sphere, ropes stretch with strain, objects expand and contract with heat. The result is that these approximations are far more accurate and precise than our measurements can ever be.
|other=High-school algebra and High-school geometry
|other=High-school algebra and High-school geometry
Revision as of 05:41, 20 May 2011
|Rope around the Earth|
Rope around the Earth
- This is a puzzle about a rope tied taut around the equator. How much must it be lenthened so that, if made to levitate, there is a one foot gap at all points between the rope and the Earth? This is a puzzle in that the answer is surprising. There is a related problem about stretching the rope taut again where the answer is even more surprising.
A question similar to this appeared in William Whiston's The Elements of Euclid circa 1702.
Smaurer1 This is burying the lead to start this way. It's irrelevant to the thrust of the article where it (first?) appeared long ago. This comment belongs at the end of the article.
Suppose a rope was tied taut around the Earth's equator. It would have the same circumference as the Earth (24,901.55 miles). The question is: by how much would the rope have to be lengthened such that, if made to hover, it would be one foot off the ground at all points around the Earth?
Despite the enormous size of the Earth, and the 1 foot gap around the entire circumference, the rope would have to be lengthened by a mere 2π feet, or roughly 6.28 feet.
In fact, this result is independent of the size of the ball around which the rope is wrapped.
A More Mathematical Explanation
- Note: understanding of this explanation requires: *High-school algebra and High-school geometry
The circumference of a circle is given by the equation: , where r is [...]
In the image to the right:
- Lrope is the length of the extended rope.
- Cearth is the Circumference of the Earth and the original length of the rope .
- Rrope is the radius of the circle made by the rope.
- Rearth is the radius of the Earth and the original radius of the rope.
When the rope is taut around the globe, its length equals the circumference of the Earth.
- (now this formula is correct)
Lengthening the rope so that it is 1 foot off the ground at all points simply means changing the radius of the circle it forms from:
- Rrope 1= Rearth
- Rrope 2= Rearth+1 ft. All this can now be simplified and the sub1-2 notation eliminated
Distributing the 2 π yields:
Now it is clear that the new length of the rope is merely 2 π feet longer than the original length. Indeed, one can see that the additional 2 π is a result of extending the radius of the rope circle by one foot, an extension that will by definition be the same no matter the initial radius of the object being enclosed.
Maximum Height of Rope
Why It's Interesting
Though it may seem that this is minuscule amount of extra rope needed to to produce such a considerable result, a look at the ratios will show otherwise.
The radius of the Earth is roughly 20,920,000 feet. There is 1 foot of difference between the radius of the circle made by the lengthened rope and the radius of the Earth. This foot of difference is a mere fraction of the radius of the Earth: about five one-hundred millionths, or .000000047, of the Earth's radius. A foot doesn't seem so large anymore.
Similarly, 2 π feet is 4.7 x 10-8 of the circumference of the Earth (which is about 131,000,000 feet). And, unsurprisingly, the ratio of 1 foot to the Earth's radius is the same as that of 2 π feet to the Earth's circumference.
So, in this perspective, a small change in the length of the rope yields a proportionally equivalent small change in the radius of the rope circle.
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- Pickover, C. A. (2009). The Math Book. New York: Sterling Publishing Co.
- (2009, March 3). Roping the Earth. Message posted to:
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