Ambiguous Case
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Law of Sines 
Congruent triangles 
Solving Triangles 
Contents
Given two adjacent side lengths and an angle opposite one of them, there is no definite completion of a triangle. According to triangle congruence postulates, two triangles cannot be proved congruent given these three elements. This configuration is commonly referred to as sidesideangle (SSA).
With the SSA configuration, there is a fixed angle connecting the base of the triangle and one of the adjacent sides. The length of the base is unknown, denoted below by a dashed line. The length of the third side length is also fixed, but neither angle adjacent to that side is known. This means that this third side can swing from the upper vertex in any way that connects this vertex and any point along the indefinitely sized base so that all three sides of the triangle are connected.
Given any SSA configuration, there are several outcomes that can occur when solving a triangle: no solution, one solution, or two solutions. Which of the three scenarios occurs for any SSA configuration depends on the length of the swinging side compared to the height of the triangle.
In any SSA configuration, we can draw the height of the triangle even though we don't know the length of the base. The height is the perpendicular distance from the upper vertex to the base. Because there is a right angle between the height and base, we can always use the fixed angle and the length of the fixed side to determine the height. Below, we will see how we can determine the number of solutions by comparing the known length of the swinging side to this known height of the triangle.
Let be the length of the side opposite , an acute angle. The table below describes the different solutions for different scenarios.
Scenario  Number of Solutions  Type of Triangle 
no solution  none  
one solution  right triangle  
two solutions  oblique  
one solution  when , equilateral/isosocles
when , obtuse 
Because the SSA configuration can prompt different numbers of solutions for for different scenarios, it is often referred to as the ambiguous case.
We can use trigonometry to determine the value of height . Click below to see how.
First Scenario: No Solution
In the first scenario, the length of the swinging side is shorter than the height, . Because this side of the triangle is shorter than the height, there is no solution. The shortest distance between a point and a given line is the line segment that is perpendicular to the given line and goes through that point, which in this case is height . Since the side length is shorter than the shortest possible distance between the base and the upper vertex of the triangle, the side opposite the fixed angle will never be able to reach the base of the triangle. Thus, there are no solutions when the swinging side length is less than or .
In the picture below with numbers we've chosen, no matter how the orange side swings, it will never touch the base of the triangle. This triangle will never be complete.

Since the other given side length is and since , there is no solution.
In summary, when , there is no solution for a SSA configuration.
Second Scenario: One Right Solution
In the second scenario, the length of the swinging side is equal to the height, . Because this side of the triangle is equal to the height, there is only one solution. The height, as explained above, is the single shortest possible distance from the upper vertex to the base of the triangle. Since the swinging side of the triangle is the same length as the height, there is only one way to orient this leg to make the triangle complete: perpendicular to the base and through the upper vertex. Thus, there is only one solution when the length is equal to or , and this automatically forms a right triangle.
In the picture below, no matter how the green side swings, it will only touch the base of the triangle once. This triangle will only be complete when the triangle becomes a right triangle.

Since the other given side length is and since , there is only one solution which is a right triangle.
In summary, when , there is just one solution for a SSA configuration.
Third Scenario: Two Solutions
In the third scenario, the length of the swinging side is greater than the height, . Because this side of the triangle is greater than the height, there are two solutions to complete the triangle. The swinging side will complete the triangle at exactly two points: one in which the swinging side and the fixed side form an acute angle, and one where those same two sides form an obtuse angle. Thus, there are two solutions when the swinging side length is greater than or
In the picture below, no matter how the blue side swings, it's endpoint will touch the base of the triangle only twice. This SSA configuration will complete two separate triangles.

Since the other given side length is and since , there is are two unique triangular completions.
In summary, when , there are two solutions for a SSA configuration.
Determining Both Solutions
The ambiguous case often produces two possible completions of the triangle. In these two potential triangles, the corresponding angles between the swinging sides and the unknown sides are supplementary. To find both triangles, use the law of sines to solve for the first triangle, then find the supplement of the measure of the angle between the swinging side and the base and solve using that angle.
Because of the cyclic nature of sine as a periodic function, the sine of a given angle is the same as the sine of its supplement. There are two solutions by the law of sines since

Fourth Scenario: One Oblique Solution
In this final scenario, the length of the swinging side is greater than the length of the fixed side. In this scenario, two possible triangles can be formed by swinging the side, but only one contains an angle of the given measure. To get one of the possible triangles, the lower endpoint of the swinging side swings past (to the left of) the vertex that connects the base and the fixed side so that the fixed angle is not included in the solution. This creates a triangle that includes the supplement of the fixed angle, but not the fixed angle. Because this fixed angle is missing from the completed triangle, this possibility is not a viable solution. Thus, there is only one solution when length is greater than length .
If , at least two of the sides of the triangle will be the same length and the solution will be either an isosceles or equilateral triangle.
In the picture below, the swinging pink side forms two triangles. The one on the left, however, does not include the fixed angle with a measure of 30 °, and is therefore not a solution for this SSA configuration.
In summary, when , there is one solutions for a SSA configuration.
Ambiguous Case Applet
Grab the point E to adjust the length of the swinging side. Grab the point B to move it around and change the height. Blue and purple triangles are solutions given the fixed angle A, the length of side AB, and the length of the swinging side. Red triangles are not viable solutions, like in the fourth scenario.
Pay attention to the numerical values on the side. You'll notice that the number of solutions depends on the length of BE compared to the height.


Teaching Materials
Ambiguous Case Demonstration
During lessons about the ambiguous case, it can often be tricky to visualize the different solutions that a particular SSA configuration produces. Sometimes, it can be easy to forget that the length of the base is not fixed, which makes it easy to forget that the two different solutions can have two differentsized bases.
This activity will show the solutions for each of the scenarios when the swinging side length is changed. Students will be able to physically see the different possible solutions given an SSA configuration. Materials Needed

Instructions
 

Sample Pictures
Click here to see sample pictures of the activity in action!
References
All of the images on this page were made by the creator/author, Richard. The applet was made by Reza.